Optimal. Leaf size=359 \[ \frac {55 i \text {ArcTan}\left (\sqrt {3}-2 \sqrt [3]{\tan (c+d x)}\right )}{72 a^2 d}-\frac {55 i \text {ArcTan}\left (\sqrt {3}+2 \sqrt [3]{\tan (c+d x)}\right )}{72 a^2 d}+\frac {8 \text {ArcTan}\left (\frac {1-2 \tan ^{\frac {2}{3}}(c+d x)}{\sqrt {3}}\right )}{3 \sqrt {3} a^2 d}-\frac {55 i \text {ArcTan}\left (\sqrt [3]{\tan (c+d x)}\right )}{36 a^2 d}+\frac {8 \log \left (1+\tan ^{\frac {2}{3}}(c+d x)\right )}{9 a^2 d}+\frac {55 i \log \left (1-\sqrt {3} \sqrt [3]{\tan (c+d x)}+\tan ^{\frac {2}{3}}(c+d x)\right )}{48 \sqrt {3} a^2 d}-\frac {55 i \log \left (1+\sqrt {3} \sqrt [3]{\tan (c+d x)}+\tan ^{\frac {2}{3}}(c+d x)\right )}{48 \sqrt {3} a^2 d}-\frac {4 \log \left (1-\tan ^{\frac {2}{3}}(c+d x)+\tan ^{\frac {4}{3}}(c+d x)\right )}{9 a^2 d}-\frac {8}{3 a^2 d \tan ^{\frac {2}{3}}(c+d x)}+\frac {11}{12 a^2 d (1+i \tan (c+d x)) \tan ^{\frac {2}{3}}(c+d x)}+\frac {1}{4 d \tan ^{\frac {2}{3}}(c+d x) (a+i a \tan (c+d x))^2} \]
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Rubi [A]
time = 0.37, antiderivative size = 359, normalized size of antiderivative = 1.00, number
of steps used = 25, number of rules used = 15, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.577, Rules
used = {3640, 3677, 3610, 3619, 3557, 335, 215, 648, 632, 210, 642, 209, 281, 298, 31}
\begin {gather*} \frac {8 \text {ArcTan}\left (\frac {1-2 \tan ^{\frac {2}{3}}(c+d x)}{\sqrt {3}}\right )}{3 \sqrt {3} a^2 d}+\frac {55 i \text {ArcTan}\left (\sqrt {3}-2 \sqrt [3]{\tan (c+d x)}\right )}{72 a^2 d}-\frac {55 i \text {ArcTan}\left (2 \sqrt [3]{\tan (c+d x)}+\sqrt {3}\right )}{72 a^2 d}-\frac {55 i \text {ArcTan}\left (\sqrt [3]{\tan (c+d x)}\right )}{36 a^2 d}-\frac {8}{3 a^2 d \tan ^{\frac {2}{3}}(c+d x)}+\frac {11}{12 a^2 d (1+i \tan (c+d x)) \tan ^{\frac {2}{3}}(c+d x)}+\frac {8 \log \left (\tan ^{\frac {2}{3}}(c+d x)+1\right )}{9 a^2 d}+\frac {55 i \log \left (\tan ^{\frac {2}{3}}(c+d x)-\sqrt {3} \sqrt [3]{\tan (c+d x)}+1\right )}{48 \sqrt {3} a^2 d}-\frac {55 i \log \left (\tan ^{\frac {2}{3}}(c+d x)+\sqrt {3} \sqrt [3]{\tan (c+d x)}+1\right )}{48 \sqrt {3} a^2 d}-\frac {4 \log \left (\tan ^{\frac {4}{3}}(c+d x)-\tan ^{\frac {2}{3}}(c+d x)+1\right )}{9 a^2 d}+\frac {1}{4 d \tan ^{\frac {2}{3}}(c+d x) (a+i a \tan (c+d x))^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 31
Rule 209
Rule 210
Rule 215
Rule 281
Rule 298
Rule 335
Rule 632
Rule 642
Rule 648
Rule 3557
Rule 3610
Rule 3619
Rule 3640
Rule 3677
Rubi steps
\begin {align*} \int \frac {1}{\tan ^{\frac {5}{3}}(c+d x) (a+i a \tan (c+d x))^2} \, dx &=\frac {1}{4 d \tan ^{\frac {2}{3}}(c+d x) (a+i a \tan (c+d x))^2}+\frac {\int \frac {\frac {14 a}{3}-\frac {8}{3} i a \tan (c+d x)}{\tan ^{\frac {5}{3}}(c+d x) (a+i a \tan (c+d x))} \, dx}{4 a^2}\\ &=\frac {11}{12 a^2 d (1+i \tan (c+d x)) \tan ^{\frac {2}{3}}(c+d x)}+\frac {1}{4 d \tan ^{\frac {2}{3}}(c+d x) (a+i a \tan (c+d x))^2}+\frac {\int \frac {\frac {128 a^2}{9}-\frac {110}{9} i a^2 \tan (c+d x)}{\tan ^{\frac {5}{3}}(c+d x)} \, dx}{8 a^4}\\ &=-\frac {8}{3 a^2 d \tan ^{\frac {2}{3}}(c+d x)}+\frac {11}{12 a^2 d (1+i \tan (c+d x)) \tan ^{\frac {2}{3}}(c+d x)}+\frac {1}{4 d \tan ^{\frac {2}{3}}(c+d x) (a+i a \tan (c+d x))^2}+\frac {\int \frac {-\frac {110 i a^2}{9}-\frac {128}{9} a^2 \tan (c+d x)}{\tan ^{\frac {2}{3}}(c+d x)} \, dx}{8 a^4}\\ &=-\frac {8}{3 a^2 d \tan ^{\frac {2}{3}}(c+d x)}+\frac {11}{12 a^2 d (1+i \tan (c+d x)) \tan ^{\frac {2}{3}}(c+d x)}+\frac {1}{4 d \tan ^{\frac {2}{3}}(c+d x) (a+i a \tan (c+d x))^2}-\frac {(55 i) \int \frac {1}{\tan ^{\frac {2}{3}}(c+d x)} \, dx}{36 a^2}-\frac {16 \int \sqrt [3]{\tan (c+d x)} \, dx}{9 a^2}\\ &=-\frac {8}{3 a^2 d \tan ^{\frac {2}{3}}(c+d x)}+\frac {11}{12 a^2 d (1+i \tan (c+d x)) \tan ^{\frac {2}{3}}(c+d x)}+\frac {1}{4 d \tan ^{\frac {2}{3}}(c+d x) (a+i a \tan (c+d x))^2}-\frac {(55 i) \text {Subst}\left (\int \frac {1}{x^{2/3} \left (1+x^2\right )} \, dx,x,\tan (c+d x)\right )}{36 a^2 d}-\frac {16 \text {Subst}\left (\int \frac {\sqrt [3]{x}}{1+x^2} \, dx,x,\tan (c+d x)\right )}{9 a^2 d}\\ &=-\frac {8}{3 a^2 d \tan ^{\frac {2}{3}}(c+d x)}+\frac {11}{12 a^2 d (1+i \tan (c+d x)) \tan ^{\frac {2}{3}}(c+d x)}+\frac {1}{4 d \tan ^{\frac {2}{3}}(c+d x) (a+i a \tan (c+d x))^2}-\frac {(55 i) \text {Subst}\left (\int \frac {1}{1+x^6} \, dx,x,\sqrt [3]{\tan (c+d x)}\right )}{12 a^2 d}-\frac {16 \text {Subst}\left (\int \frac {x^3}{1+x^6} \, dx,x,\sqrt [3]{\tan (c+d x)}\right )}{3 a^2 d}\\ &=-\frac {8}{3 a^2 d \tan ^{\frac {2}{3}}(c+d x)}+\frac {11}{12 a^2 d (1+i \tan (c+d x)) \tan ^{\frac {2}{3}}(c+d x)}+\frac {1}{4 d \tan ^{\frac {2}{3}}(c+d x) (a+i a \tan (c+d x))^2}-\frac {(55 i) \text {Subst}\left (\int \frac {1}{1+x^2} \, dx,x,\sqrt [3]{\tan (c+d x)}\right )}{36 a^2 d}-\frac {(55 i) \text {Subst}\left (\int \frac {1-\frac {\sqrt {3} x}{2}}{1-\sqrt {3} x+x^2} \, dx,x,\sqrt [3]{\tan (c+d x)}\right )}{36 a^2 d}-\frac {(55 i) \text {Subst}\left (\int \frac {1+\frac {\sqrt {3} x}{2}}{1+\sqrt {3} x+x^2} \, dx,x,\sqrt [3]{\tan (c+d x)}\right )}{36 a^2 d}-\frac {8 \text {Subst}\left (\int \frac {x}{1+x^3} \, dx,x,\tan ^{\frac {2}{3}}(c+d x)\right )}{3 a^2 d}\\ &=-\frac {55 i \tan ^{-1}\left (\sqrt [3]{\tan (c+d x)}\right )}{36 a^2 d}-\frac {8}{3 a^2 d \tan ^{\frac {2}{3}}(c+d x)}+\frac {11}{12 a^2 d (1+i \tan (c+d x)) \tan ^{\frac {2}{3}}(c+d x)}+\frac {1}{4 d \tan ^{\frac {2}{3}}(c+d x) (a+i a \tan (c+d x))^2}-\frac {(55 i) \text {Subst}\left (\int \frac {1}{1-\sqrt {3} x+x^2} \, dx,x,\sqrt [3]{\tan (c+d x)}\right )}{144 a^2 d}-\frac {(55 i) \text {Subst}\left (\int \frac {1}{1+\sqrt {3} x+x^2} \, dx,x,\sqrt [3]{\tan (c+d x)}\right )}{144 a^2 d}+\frac {8 \text {Subst}\left (\int \frac {1}{1+x} \, dx,x,\tan ^{\frac {2}{3}}(c+d x)\right )}{9 a^2 d}-\frac {8 \text {Subst}\left (\int \frac {1+x}{1-x+x^2} \, dx,x,\tan ^{\frac {2}{3}}(c+d x)\right )}{9 a^2 d}+\frac {(55 i) \text {Subst}\left (\int \frac {-\sqrt {3}+2 x}{1-\sqrt {3} x+x^2} \, dx,x,\sqrt [3]{\tan (c+d x)}\right )}{48 \sqrt {3} a^2 d}-\frac {(55 i) \text {Subst}\left (\int \frac {\sqrt {3}+2 x}{1+\sqrt {3} x+x^2} \, dx,x,\sqrt [3]{\tan (c+d x)}\right )}{48 \sqrt {3} a^2 d}\\ &=-\frac {55 i \tan ^{-1}\left (\sqrt [3]{\tan (c+d x)}\right )}{36 a^2 d}+\frac {8 \log \left (1+\tan ^{\frac {2}{3}}(c+d x)\right )}{9 a^2 d}+\frac {55 i \log \left (1-\sqrt {3} \sqrt [3]{\tan (c+d x)}+\tan ^{\frac {2}{3}}(c+d x)\right )}{48 \sqrt {3} a^2 d}-\frac {55 i \log \left (1+\sqrt {3} \sqrt [3]{\tan (c+d x)}+\tan ^{\frac {2}{3}}(c+d x)\right )}{48 \sqrt {3} a^2 d}-\frac {8}{3 a^2 d \tan ^{\frac {2}{3}}(c+d x)}+\frac {11}{12 a^2 d (1+i \tan (c+d x)) \tan ^{\frac {2}{3}}(c+d x)}+\frac {1}{4 d \tan ^{\frac {2}{3}}(c+d x) (a+i a \tan (c+d x))^2}+\frac {(55 i) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,-\sqrt {3}+2 \sqrt [3]{\tan (c+d x)}\right )}{72 a^2 d}+\frac {(55 i) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,\sqrt {3}+2 \sqrt [3]{\tan (c+d x)}\right )}{72 a^2 d}-\frac {4 \text {Subst}\left (\int \frac {-1+2 x}{1-x+x^2} \, dx,x,\tan ^{\frac {2}{3}}(c+d x)\right )}{9 a^2 d}-\frac {4 \text {Subst}\left (\int \frac {1}{1-x+x^2} \, dx,x,\tan ^{\frac {2}{3}}(c+d x)\right )}{3 a^2 d}\\ &=\frac {55 i \tan ^{-1}\left (\sqrt {3}-2 \sqrt [3]{\tan (c+d x)}\right )}{72 a^2 d}-\frac {55 i \tan ^{-1}\left (\sqrt {3}+2 \sqrt [3]{\tan (c+d x)}\right )}{72 a^2 d}-\frac {55 i \tan ^{-1}\left (\sqrt [3]{\tan (c+d x)}\right )}{36 a^2 d}+\frac {8 \log \left (1+\tan ^{\frac {2}{3}}(c+d x)\right )}{9 a^2 d}+\frac {55 i \log \left (1-\sqrt {3} \sqrt [3]{\tan (c+d x)}+\tan ^{\frac {2}{3}}(c+d x)\right )}{48 \sqrt {3} a^2 d}-\frac {55 i \log \left (1+\sqrt {3} \sqrt [3]{\tan (c+d x)}+\tan ^{\frac {2}{3}}(c+d x)\right )}{48 \sqrt {3} a^2 d}-\frac {4 \log \left (1-\tan ^{\frac {2}{3}}(c+d x)+\tan ^{\frac {4}{3}}(c+d x)\right )}{9 a^2 d}-\frac {8}{3 a^2 d \tan ^{\frac {2}{3}}(c+d x)}+\frac {11}{12 a^2 d (1+i \tan (c+d x)) \tan ^{\frac {2}{3}}(c+d x)}+\frac {1}{4 d \tan ^{\frac {2}{3}}(c+d x) (a+i a \tan (c+d x))^2}+\frac {8 \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,-1+2 \tan ^{\frac {2}{3}}(c+d x)\right )}{3 a^2 d}\\ &=\frac {55 i \tan ^{-1}\left (\sqrt {3}-2 \sqrt [3]{\tan (c+d x)}\right )}{72 a^2 d}-\frac {55 i \tan ^{-1}\left (\sqrt {3}+2 \sqrt [3]{\tan (c+d x)}\right )}{72 a^2 d}+\frac {8 \tan ^{-1}\left (\frac {1-2 \tan ^{\frac {2}{3}}(c+d x)}{\sqrt {3}}\right )}{3 \sqrt {3} a^2 d}-\frac {55 i \tan ^{-1}\left (\sqrt [3]{\tan (c+d x)}\right )}{36 a^2 d}+\frac {8 \log \left (1+\tan ^{\frac {2}{3}}(c+d x)\right )}{9 a^2 d}+\frac {55 i \log \left (1-\sqrt {3} \sqrt [3]{\tan (c+d x)}+\tan ^{\frac {2}{3}}(c+d x)\right )}{48 \sqrt {3} a^2 d}-\frac {55 i \log \left (1+\sqrt {3} \sqrt [3]{\tan (c+d x)}+\tan ^{\frac {2}{3}}(c+d x)\right )}{48 \sqrt {3} a^2 d}-\frac {4 \log \left (1-\tan ^{\frac {2}{3}}(c+d x)+\tan ^{\frac {4}{3}}(c+d x)\right )}{9 a^2 d}-\frac {8}{3 a^2 d \tan ^{\frac {2}{3}}(c+d x)}+\frac {11}{12 a^2 d (1+i \tan (c+d x)) \tan ^{\frac {2}{3}}(c+d x)}+\frac {1}{4 d \tan ^{\frac {2}{3}}(c+d x) (a+i a \tan (c+d x))^2}\\ \end {align*}
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Mathematica [C] Result contains higher order function than in optimal. Order 5 vs. order 3 in
optimal.
time = 3.98, size = 205, normalized size = 0.57 \begin {gather*} \frac {\sec (c+d x) \left (-\frac {36 i 2^{2/3} e^{3 i (c+d x)} \, _2F_1\left (\frac {1}{3},\frac {1}{3};\frac {4}{3};\frac {1}{2} \left (1-e^{2 i (c+d x)}\right )\right )}{\left (1+e^{2 i (c+d x)}\right )^{2/3}}+476 i \, _2F_1\left (\frac {1}{3},1;\frac {4}{3};-\frac {-1+e^{2 i (c+d x)}}{1+e^{2 i (c+d x)}}\right ) (\cos (2 (c+d x)) \sec (c+d x)+2 i \sin (c+d x))+4 \csc (c+d x) (-14+50 \cos (2 (c+d x))+53 i \sin (2 (c+d x)))\right ) \sqrt [3]{\tan (c+d x)}}{96 a^2 d (-i+\tan (c+d x))^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.21, size = 233, normalized size = 0.65
method | result | size |
derivativedivides | \(\frac {-\frac {5 i}{12 \left (\tan ^{\frac {1}{3}}\left (d x +c \right )+i\right )}+\frac {1}{36 \left (\tan ^{\frac {1}{3}}\left (d x +c \right )+i\right )^{2}}+\frac {119 \ln \left (\tan ^{\frac {1}{3}}\left (d x +c \right )+i\right )}{72}-\frac {\ln \left (i \left (\tan ^{\frac {1}{3}}\left (d x +c \right )\right )+\tan ^{\frac {2}{3}}\left (d x +c \right )-1\right )}{16}+\frac {i \sqrt {3}\, \arctanh \left (\frac {\left (i+2 \left (\tan ^{\frac {1}{3}}\left (d x +c \right )\right )\right ) \sqrt {3}}{3}\right )}{8}+\frac {30 i \tan \left (d x +c \right )+4 \left (\tan ^{\frac {2}{3}}\left (d x +c \right )\right )-4 i \left (\tan ^{\frac {1}{3}}\left (d x +c \right )\right )+32}{72 \left (-i \left (\tan ^{\frac {1}{3}}\left (d x +c \right )\right )+\tan ^{\frac {2}{3}}\left (d x +c \right )-1\right )^{2}}-\frac {119 \ln \left (-i \left (\tan ^{\frac {1}{3}}\left (d x +c \right )\right )+\tan ^{\frac {2}{3}}\left (d x +c \right )-1\right )}{144}-\frac {119 i \sqrt {3}\, \arctanh \left (\frac {\left (-i+2 \left (\tan ^{\frac {1}{3}}\left (d x +c \right )\right )\right ) \sqrt {3}}{3}\right )}{72}-\frac {3}{2 \tan \left (d x +c \right )^{\frac {2}{3}}}+\frac {\ln \left (\tan ^{\frac {1}{3}}\left (d x +c \right )-i\right )}{8}}{d \,a^{2}}\) | \(233\) |
default | \(\frac {-\frac {5 i}{12 \left (\tan ^{\frac {1}{3}}\left (d x +c \right )+i\right )}+\frac {1}{36 \left (\tan ^{\frac {1}{3}}\left (d x +c \right )+i\right )^{2}}+\frac {119 \ln \left (\tan ^{\frac {1}{3}}\left (d x +c \right )+i\right )}{72}-\frac {\ln \left (i \left (\tan ^{\frac {1}{3}}\left (d x +c \right )\right )+\tan ^{\frac {2}{3}}\left (d x +c \right )-1\right )}{16}+\frac {i \sqrt {3}\, \arctanh \left (\frac {\left (i+2 \left (\tan ^{\frac {1}{3}}\left (d x +c \right )\right )\right ) \sqrt {3}}{3}\right )}{8}+\frac {30 i \tan \left (d x +c \right )+4 \left (\tan ^{\frac {2}{3}}\left (d x +c \right )\right )-4 i \left (\tan ^{\frac {1}{3}}\left (d x +c \right )\right )+32}{72 \left (-i \left (\tan ^{\frac {1}{3}}\left (d x +c \right )\right )+\tan ^{\frac {2}{3}}\left (d x +c \right )-1\right )^{2}}-\frac {119 \ln \left (-i \left (\tan ^{\frac {1}{3}}\left (d x +c \right )\right )+\tan ^{\frac {2}{3}}\left (d x +c \right )-1\right )}{144}-\frac {119 i \sqrt {3}\, \arctanh \left (\frac {\left (-i+2 \left (\tan ^{\frac {1}{3}}\left (d x +c \right )\right )\right ) \sqrt {3}}{3}\right )}{72}-\frac {3}{2 \tan \left (d x +c \right )^{\frac {2}{3}}}+\frac {\ln \left (\tan ^{\frac {1}{3}}\left (d x +c \right )-i\right )}{8}}{d \,a^{2}}\) | \(233\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RuntimeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Both result and optimal contain complex but leaf count of result is larger than twice
the leaf count of optimal. 681 vs. \(2 (282) = 564\).
time = 0.63, size = 681, normalized size = 1.90 \begin {gather*} -\frac {9 \, {\left (\sqrt {3} {\left (-i \, a^{2} d e^{\left (6 i \, d x + 6 i \, c\right )} + i \, a^{2} d e^{\left (4 i \, d x + 4 i \, c\right )}\right )} \sqrt {\frac {1}{a^{4} d^{2}}} + e^{\left (6 i \, d x + 6 i \, c\right )} - e^{\left (4 i \, d x + 4 i \, c\right )}\right )} \log \left (\frac {1}{2} \, \sqrt {3} a^{2} d \sqrt {\frac {1}{a^{4} d^{2}}} + \left (\frac {-i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}\right )^{\frac {1}{3}} + \frac {1}{2} i\right ) + 9 \, {\left (\sqrt {3} {\left (i \, a^{2} d e^{\left (6 i \, d x + 6 i \, c\right )} - i \, a^{2} d e^{\left (4 i \, d x + 4 i \, c\right )}\right )} \sqrt {\frac {1}{a^{4} d^{2}}} + e^{\left (6 i \, d x + 6 i \, c\right )} - e^{\left (4 i \, d x + 4 i \, c\right )}\right )} \log \left (-\frac {1}{2} \, \sqrt {3} a^{2} d \sqrt {\frac {1}{a^{4} d^{2}}} + \left (\frac {-i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}\right )^{\frac {1}{3}} + \frac {1}{2} i\right ) + 119 \, {\left (3 \, \sqrt {\frac {1}{3}} {\left (i \, a^{2} d e^{\left (6 i \, d x + 6 i \, c\right )} - i \, a^{2} d e^{\left (4 i \, d x + 4 i \, c\right )}\right )} \sqrt {\frac {1}{a^{4} d^{2}}} + e^{\left (6 i \, d x + 6 i \, c\right )} - e^{\left (4 i \, d x + 4 i \, c\right )}\right )} \log \left (\frac {3}{2} \, \sqrt {\frac {1}{3}} a^{2} d \sqrt {\frac {1}{a^{4} d^{2}}} + \left (\frac {-i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}\right )^{\frac {1}{3}} - \frac {1}{2} i\right ) + 119 \, {\left (3 \, \sqrt {\frac {1}{3}} {\left (-i \, a^{2} d e^{\left (6 i \, d x + 6 i \, c\right )} + i \, a^{2} d e^{\left (4 i \, d x + 4 i \, c\right )}\right )} \sqrt {\frac {1}{a^{4} d^{2}}} + e^{\left (6 i \, d x + 6 i \, c\right )} - e^{\left (4 i \, d x + 4 i \, c\right )}\right )} \log \left (-\frac {3}{2} \, \sqrt {\frac {1}{3}} a^{2} d \sqrt {\frac {1}{a^{4} d^{2}}} + \left (\frac {-i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}\right )^{\frac {1}{3}} - \frac {1}{2} i\right ) - 238 \, {\left (e^{\left (6 i \, d x + 6 i \, c\right )} - e^{\left (4 i \, d x + 4 i \, c\right )}\right )} \log \left (\left (\frac {-i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}\right )^{\frac {1}{3}} + i\right ) - 18 \, {\left (e^{\left (6 i \, d x + 6 i \, c\right )} - e^{\left (4 i \, d x + 4 i \, c\right )}\right )} \log \left (\left (\frac {-i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}\right )^{\frac {1}{3}} - i\right ) + 3 \, \left (\frac {-i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} + 1}\right )^{\frac {1}{3}} {\left (103 i \, e^{\left (6 i \, d x + 6 i \, c\right )} + 75 i \, e^{\left (4 i \, d x + 4 i \, c\right )} - 31 i \, e^{\left (2 i \, d x + 2 i \, c\right )} - 3 i\right )}}{144 \, {\left (a^{2} d e^{\left (6 i \, d x + 6 i \, c\right )} - a^{2} d e^{\left (4 i \, d x + 4 i \, c\right )}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 2.05, size = 238, normalized size = 0.66 \begin {gather*} \frac {119 i \, \sqrt {3} \log \left (-\frac {\sqrt {3} - 2 \, \tan \left (d x + c\right )^{\frac {1}{3}} + i}{\sqrt {3} + 2 \, \tan \left (d x + c\right )^{\frac {1}{3}} - i}\right )}{144 \, a^{2} d} - \frac {i \, \sqrt {3} \log \left (-\frac {\sqrt {3} - 2 \, \tan \left (d x + c\right )^{\frac {1}{3}} - i}{\sqrt {3} + 2 \, \tan \left (d x + c\right )^{\frac {1}{3}} + i}\right )}{16 \, a^{2} d} - \frac {\log \left (\tan \left (d x + c\right )^{\frac {2}{3}} + i \, \tan \left (d x + c\right )^{\frac {1}{3}} - 1\right )}{16 \, a^{2} d} - \frac {119 \, \log \left (\tan \left (d x + c\right )^{\frac {2}{3}} - i \, \tan \left (d x + c\right )^{\frac {1}{3}} - 1\right )}{144 \, a^{2} d} + \frac {119 \, \log \left (\tan \left (d x + c\right )^{\frac {1}{3}} + i\right )}{72 \, a^{2} d} + \frac {\log \left (\tan \left (d x + c\right )^{\frac {1}{3}} - i\right )}{8 \, a^{2} d} - \frac {32 \, \tan \left (d x + c\right )^{2} - 53 i \, \tan \left (d x + c\right ) - 18}{12 \, {\left (\tan \left (d x + c\right )^{\frac {4}{3}} - i \, \tan \left (d x + c\right )^{\frac {1}{3}}\right )}^{2} a^{2} d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 5.26, size = 660, normalized size = 1.84 \begin {gather*} \ln \left (\left (28311552\,a^{10}\,d^5\,{\mathrm {tan}\left (c+d\,x\right )}^{1/3}\,{\left (\frac {1}{512\,a^6\,d^3}\right )}^{2/3}+\frac {a^6\,d^3\,215607040{}\mathrm {i}}{3}\right )\,{\left (\frac {1}{512\,a^6\,d^3}\right )}^{1/3}-\frac {27116768\,a^4\,d^2\,{\mathrm {tan}\left (c+d\,x\right )}^{1/3}}{3}\right )\,{\left (\frac {1}{512\,a^6\,d^3}\right )}^{1/3}+\frac {119\,\ln \left (\frac {119\,\left (\frac {232013824\,a^{10}\,d^5\,{\mathrm {tan}\left (c+d\,x\right )}^{1/3}\,{\left (\frac {1}{a^6\,d^3}\right )}^{2/3}}{3}+\frac {a^6\,d^3\,215607040{}\mathrm {i}}{3}\right )\,{\left (\frac {1}{a^6\,d^3}\right )}^{1/3}}{72}-\frac {27116768\,a^4\,d^2\,{\mathrm {tan}\left (c+d\,x\right )}^{1/3}}{3}\right )\,{\left (\frac {1}{a^6\,d^3}\right )}^{1/3}}{72}-\frac {\frac {53\,\mathrm {tan}\left (c+d\,x\right )}{12\,a^2\,d}-\frac {3{}\mathrm {i}}{2\,a^2\,d}+\frac {{\mathrm {tan}\left (c+d\,x\right )}^2\,8{}\mathrm {i}}{3\,a^2\,d}}{2\,{\mathrm {tan}\left (c+d\,x\right )}^{5/3}-{\mathrm {tan}\left (c+d\,x\right )}^{2/3}\,1{}\mathrm {i}+{\mathrm {tan}\left (c+d\,x\right )}^{8/3}\,1{}\mathrm {i}}+\ln \left (\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (\frac {a^6\,d^3\,215607040{}\mathrm {i}}{3}+28311552\,a^{10}\,d^5\,{\mathrm {tan}\left (c+d\,x\right )}^{1/3}\,{\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}^2\,{\left (\frac {1}{512\,a^6\,d^3}\right )}^{2/3}\right )\,{\left (\frac {1}{512\,a^6\,d^3}\right )}^{1/3}-\frac {27116768\,a^4\,d^2\,{\mathrm {tan}\left (c+d\,x\right )}^{1/3}}{3}\right )\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,{\left (\frac {1}{512\,a^6\,d^3}\right )}^{1/3}-\ln \left (\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (\frac {a^6\,d^3\,215607040{}\mathrm {i}}{3}+28311552\,a^{10}\,d^5\,{\mathrm {tan}\left (c+d\,x\right )}^{1/3}\,{\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )}^2\,{\left (\frac {1}{512\,a^6\,d^3}\right )}^{2/3}\right )\,{\left (\frac {1}{512\,a^6\,d^3}\right )}^{1/3}+\frac {27116768\,a^4\,d^2\,{\mathrm {tan}\left (c+d\,x\right )}^{1/3}}{3}\right )\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,{\left (\frac {1}{512\,a^6\,d^3}\right )}^{1/3}+\frac {119\,\ln \left (\frac {119\,\left (-1+\sqrt {3}\,1{}\mathrm {i}\right )\,\left (\frac {a^6\,d^3\,215607040{}\mathrm {i}}{3}+\frac {58003456\,a^{10}\,d^5\,{\mathrm {tan}\left (c+d\,x\right )}^{1/3}\,{\left (-1+\sqrt {3}\,1{}\mathrm {i}\right )}^2\,{\left (\frac {1}{a^6\,d^3}\right )}^{2/3}}{3}\right )\,{\left (\frac {1}{a^6\,d^3}\right )}^{1/3}}{144}-\frac {27116768\,a^4\,d^2\,{\mathrm {tan}\left (c+d\,x\right )}^{1/3}}{3}\right )\,\left (-1+\sqrt {3}\,1{}\mathrm {i}\right )\,{\left (\frac {1}{a^6\,d^3}\right )}^{1/3}}{144}-\frac {119\,\ln \left (\frac {119\,\left (1+\sqrt {3}\,1{}\mathrm {i}\right )\,\left (\frac {a^6\,d^3\,215607040{}\mathrm {i}}{3}+\frac {58003456\,a^{10}\,d^5\,{\mathrm {tan}\left (c+d\,x\right )}^{1/3}\,{\left (1+\sqrt {3}\,1{}\mathrm {i}\right )}^2\,{\left (\frac {1}{a^6\,d^3}\right )}^{2/3}}{3}\right )\,{\left (\frac {1}{a^6\,d^3}\right )}^{1/3}}{144}+\frac {27116768\,a^4\,d^2\,{\mathrm {tan}\left (c+d\,x\right )}^{1/3}}{3}\right )\,\left (1+\sqrt {3}\,1{}\mathrm {i}\right )\,{\left (\frac {1}{a^6\,d^3}\right )}^{1/3}}{144} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
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